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144=2x^2+x
We move all terms to the left:
144-(2x^2+x)=0
We get rid of parentheses
-2x^2-x+144=0
We add all the numbers together, and all the variables
-2x^2-1x+144=0
a = -2; b = -1; c = +144;
Δ = b2-4ac
Δ = -12-4·(-2)·144
Δ = 1153
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{1153}}{2*-2}=\frac{1-\sqrt{1153}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{1153}}{2*-2}=\frac{1+\sqrt{1153}}{-4} $
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